On Feb 3, 12:41 pm, monirr <muni...@hotmail.com> wrote:
> ok here is my problem i'm new to cake and i bulid every thing ok so i have
> categories and recipes categories has many recipes , recipes belongs to
> categories i wanna access recipes by categories
> this for my public website
> what code should i put in order to access it by link and shows the recipes
> in that categories
>
> this is my categories table strucature
> Id
> Name
> Area
> Slug =>this one i made it so it can act as slug
> Active
>
> this my categories "index"
>
> a<?php $paginator->options(array('url' => $this->passedArgs)); ?>
> <table cellpadding="0" cellspacing="0">
> <tr id="categoriesSorting">
>
> </tr>
> <?php
> $i = 0;
> foreach ($categories as $category):
> $class = null;
> if ($i++ % 2 == 0) {
> $class = ' class="altrow"';
> }
> ?>
> <tr<?php echo $class;?>>
>
> <?=$html->link('<h3>'.$category['Category']['name'].'</h3>','/categories/view/'.$category['Category']
> ['slug'],null,null,false);?>
>
> <?php endforeach; ?>
> </table>
> <div class="paging" id="categoriesPaging">
> <?php echo $paginator->prev('<< '.__('previous', true), array(), null,
> array('class'=>'disabled'));?>
> | <?php echo $paginator->numbers();?>
> <?php echo $paginator->next(__('next', true).' >>', array(), null,
> array('class'=>'disabled'));?>
> </div>
>
> and this is my "view"
>
> <h2><?php __('Recipes By Category');?></h2>
>
> <br />
> <table>
>
> <?=$html->link('<h3>'.$category['Category']['name'].'</h3>','/recipes/view/'.$category['Category']
> ['slug'],null,null,false);?>
>
> </table>
> </div>
>
> <div class="clear"> </div>
>
> </div>
>
> </div>
>
> <script type="text/javascript">
> $("#tabpanel > ul").tabs();
> </script>
>
> and one more thing
> when i click on categories lets say "new" it takes me to the view u know
> then i can see the link
> --
> View this message in context:http://www.nabble.com/help-plz-tp21814971p21814971.html
> Sent from the CakePHP mailing list archive at Nabble.com.
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Wednesday, February 4, 2009
Re: help plz
read the manual.
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