Re: Problem returning array from function

Im sorry, I really dont get this

> the returned (reversedarray)
> is lost in the null land, because no variable is defined to receive
> id!

If $id = 0 I dont need it to be added to the array - the array is now
complete so I want to take the array ive built to date and exit the
function

> And the $arraywill just contain the values as before the call
> (recursive) to thefunction.

Thats just what I want

> And furthermore, I don't see any statement returning anything from
> hereon!

Shouldn't return $reverse; be enough to return my array?

On Jun 29, 9:04 pm, John Andersen <j.andersen...@gmail.com> wrote:
> Assuming you are passing anarraywith one ID, then if I understand
> your problem correctly, a parent will be read from the database and as
> it will not be 0, thefunctionwill enter the else statement.
>
> There is will add the parent ID to thearrayand then pass thisarray
> plus the parent ID via a recursive call to thefunction.
>
> In the (recursive)functiona parent will be read and it will be 0,
> thus entering into the main if statement, where thearrayis reversed,
> and returned ...
>
> ... returning to thefunction... ups, the returned (reversedarray)
> is lost in the null land, because no variable is defined to receive
> id! And the $arraywill just contain the values as before the call
> (recursive) to thefunction.
>
> And furthermore, I don't see any statement returning anything from
> hereon!
>
> Please check your code !! Turn on Debug, add debug statements and try
> again!
> Enjoy,
>    John
>
> On Jun 28, 11:53 pm, Sanfly <san...@gmail.com> wrote:
>
> > No, I dont think so.  I have no trouble building thearraybecause
> > this line:
>
> > print_r($reverse); echo "<br><br>";
>
> > does print the entire correctarray.  Its returning it from the
> >functionwhen there is more than one value in thearraythat gives me
> > a problem.
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