Re: Logout link in layout

in you app_controller.php, put this
public function beforeRender() {
if (!array_key_exists('requested', $this->params)) {
$user = $this->Session->read($this->Auth->sessionKey);
$this->set(compact('user'));
}
}

and in the layout put this

if (!empty($user))
echo $html->link('Logout', array('controller' => 'Users',
'action'=>'logout'));

and the happy new year
On Dec 24, 4:46 am, emmexx <emmeics...@gmail.com> wrote:
> I'd like to put a logout link in my default layout. The link should be
> there only when a user has already logged in.
> I put the following code in my app/views/layouts/default.ctp:
>
> if ($this->Auth->user())
>         echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));
>
> but, of course, cake didn't like and screamed in horror:
>
> Notice (8): Undefined property:  View::$Auth [APP/views/elements/
> logout.ctp, line 3]
>
> Fatal error: Call to a member function user() on a non-object in /app/
> views/elements/logout.ctp on line 3
>
> Is there a way to accomplish that?
>
> Thank you and Merry Christmas!
>
>    maxx

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