Re: Logout link in layout

If(isset($this->Session->read('User.id'))):
> echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));

endif;

happy christmas

Em 24/12/2009, às 07:46, emmexx escreveu:

> I'd like to put a logout link in my default layout. The link should be
> there only when a user has already logged in.
> I put the following code in my app/views/layouts/default.ctp:
>
> if ($this->Auth->user())
> echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));
>
> but, of course, cake didn't like and screamed in horror:
>
> Notice (8): Undefined property: View::$Auth [APP/views/elements/
> logout.ctp, line 3]
>
> Fatal error: Call to a member function user() on a non-object in /app/
> views/elements/logout.ctp on line 3
>
> Is there a way to accomplish that?
>
> Thank you and Merry Christmas!
>
> maxx
>
> Check out the new CakePHP Questions site http://cakeqs.org and help
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Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions.

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