RE: JSON View

Hey,
Simply include

$this->layout = 'ajax';
$this->autoLayout = false;
$this->autoRender = false;

In the controller action to stop the view from output. All you get is the
json data then do what you need with it

Dave
-----Original Message-----
From: cake-php@googlegroups.com [mailto:cake-php@googlegroups.com] On Behalf
Of thomaus
Sent: January-28-10 9:08 AM
To: CakePHP
Subject: Re: JSON View

Hi there,

I need to render a full HTML view with header, css and js includes and pass
it as a JSON.

I liked Dave's trick :

$response['html'] = $this->render('my_view_needed'); Then echo back my
json_encode($response) and use response.html in the js to render the view /
messages / errors.

But there is a problem, when you do : $response['html'] = $this->render
('my_view_needed'); it correctly puts all the HTML view content in your
$response['html'] var but still it outputs the view content just after so
the JSON callback format is incorrect. Is there a way to get the content of
a view render without rendering it?

Otherwise how can I do if I want to send the full HTML content of my view as
a JSON callback?

Thanks in advance.

On Jan 21, 8:03 am, Akeda Bagus <ad...@gedex.web.id> wrote:
> On Mon, Jan 11, 2010 at 10:50 PM, Dave <make.cake.b...@gmail.com> wrote:
> > Does anyone know how to return a JSON object from an ajax request to
> > return the view and a success status? I see all these tutorials to
> > retrn data but no html. Everything is layout = false, autoRender =
> > false. I can return the view in normal html but I need to get a
> > status = true or false to the js to tell it what to do next
> > depending on the status. I need to update 1 of 2 possible divs with
> > the response and that's why I need the success to tell the js if success
update this div if no success then do something different.
>
> > I need to return a view along with my success or fail status. Not
> > just an error message as I have found in my json / cakephp searching.
>
> > so in the controller
> > $this->layout = 'ajax';
> > if(this->Model->save())
> > {
> > //return success = true and success view $respounse = array('status'
> > => true, 'html' => ???
>
> > } else {
>
> >  //return false
> >  $respounse = array('status' => false); }
> > $this->header('Content-Type: application/json');
> >        echo json_encode($response);
>
> > Ideas?
>
> My approach is:
> 1. create json layout in views/layout/json/default.ctp which contains:
> <?php
> header("Pragma: no-cache");
> header("Cache-Control: no-store, no-cache, max-age=0,
> must-revalidate");
> header('Content-Type: application/json');
>
> echo $content_for_layout;
> ?>
>
> 2. create common view for json, says app/views/common/jsonize.ctp --
> my controllers use this oftenly, which contains:
> <?php echo $javascript->object($result); ?>
>
> 3. I put jsonize in app_controller.php, so other controllers will benefit
this:
> function jsonize() {
>     $this->layout = 'json/default';
>     $this->viewPath = "common";
>
>     if ( Configure::read('debug') > 0 ) {
>         Configure::write('debug', 0);
>     }
>
>     if ( !$this->params['named'] ) {
>         $this->Session->setFlash('Invalid parameter for JSON',
> 'error');
>         $this->redirect(array('action'=>'index'));
>     }
>
>     foreach ($this->params['named'] as $field => $value) {
>         $like = str_replace('*', '%', $value);
>         $condition[Inflector::singularize($this->name).".$field LIKE"]
> = $like;
>     }
>     $this->{Inflector::singularize($this->name)}->recursive = -1;
>     $result =
> $this->{Inflector::singularize($this->name)}->find('all',
> array( 'conditions' => $condition ));
>     $this->set('result', $result);
>
> }
>
> It just a little modification is you used on $this->Model->save()
>
> --
> regards,
> gedex
>
> blog:http://gedex.web.id

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