I am 99% sure that doesn't return the content, it just triggers cakes
view rendering process.
On Apr 5, 4:05 pm, "Dave" <make.cake.b...@gmail.com> wrote:
> I had same issue but solved it with adding exit(); where you have return
> null;.
>
> Dave
>
> -----Original Message-----
> From: cake-php@googlegroups.com [mailto:cake-php@googlegroups.com] On Behalf
>
> Of cricket
> Sent: April-05-10 8:02 PM
> To: CakePHP
> Subject: echo JSON
>
> I'm having some trouble sending JSON back to a JS AJAX function. What I need
> to do is save some data, then send it back for previewing. The AJAX function
> should display it in a modal window. However, I also need to send back the
> model ID in the case that the record has only just been created. That way,
> the JS function can add the hidden model ID input so subsequent previews
> won't save a new record.
>
> Anyway, alerting the response shows I'm getting the JSON object, plus a 2nd
> string containing the rendered view. I can't figure out why Cake is echoing
> this.
>
> Here's what I've got:
>
> public function admin_preview($id = null) {
> $this->layout = null;
> $this->autoLayout = $this->autoRender = false;
> $this->viewPath = 'elements/email/text';
> Configure::write('debug', 0);
>
> if (!empty($this->data))
> {
> $data = $this->Newsletter->save($this->data);
> }
> else if (isset($id))
> {
> $data = $this->Newsletter->read(null, $id);
> }
> else
> {
> return null;
> }
>
> $data['Newsletter']['nice_date'] = niceDate(date('Y-m-d'));
> $this->set(compact('data'));
>
> echo json_encode(
> array(
> 'id' => $this->Newsletter->id,
> 'content' => $this->render('newsletter')
> )
> );
> return null;
> }
>
> This results in a proper JSON object with id & content, plus the rendered
> content again.
>
> I tried return json_encode(...) but, strangely, that results in just the
> rendered view. What's going on?!
>
> Check out the new CakePHP Questions sitehttp://cakeqs.organd help others
> with their CakePHP related questions.
>
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