Re: Cake 2.0.4 : how to display "logout" if logged, else display "login"

I never used previous versions, I found this by searching a little on
the net.

So it's more like :

<?php
if ($this->Session('Auth')) {
echo("logged");
}
else {
echo("not logged");
}
?>

?

Thanks a lot for your help !

On 23 déc, 19:41, euromark <dereurom...@googlemail.com> wrote:
> $session was already outdated in 1.3
>
> $this->Session is the correct usage
>
> On 23 Dez., 17:26, JonStark <jean...@gmail.com> wrote:
>
>
>
>
>
>
>
> > I want to do this on cake 2.0.4 (new to cake), but this does'nt work:
>
> >         <?php
> >          if ($session->read('Auth')) {
> >                 echo("logged");
> >                 }
>
> >          else {
> >                 echo("not logged");
> >                 }
> >         ?>
>
> > Thanks a lot for your help !

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