Re: Cake 2.0.4 : how to display "logout" if logged, else display "login"

Indeed, stupid mistake... Thanks again ! I need to be more careful.

This works :

<?php
$addlink = $this->Html->url('/items/add');

if ($this->Session->check('Auth.User.id')) {
echo ("

<div class='well' style='padding: 16px 19px;'>
<a href='$addlink' class='btn
primary small'>Add an activity</a>
</div>

");
} else
{
echo ("");
}

?>

On 24 déc, 11:25, euromark <dereurom...@googlemail.com> wrote:
> it does cause the problem :)
> usually a good IDEA would automatically display a parse error
>
> On 24 Dez., 02:52, Geoff Douglas <drdouglas...@gmail.com> wrote:
>
>
>
>
>
>
>
> > Under the logged in condition... you are using double quotes twice... could
> > cause a problem.

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