$Office->find('all', array(
...
'contain' => array(//or 'contains' -> check manual ;)
'Company' => array('fields' => array('name')),
'Person' => array(
'fields' => array('mail'),
'OfficePersonTask' => array( )
'Office' => array('fields' => 'name'),
'Task' => array('fields' => 'name'),
),
),
...
));
Or try setting the fields names in $hasMany, $hasOne, etc array http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasone
On Tuesday, July 31, 2012 12:16:38 PM UTC+2, Mariano C. wrote:
--In CakePHP 2.1 I have prepared a Json webservice. This is an excerpt of what I get:{
Offices:[
{
Office:{
id:"1",
Company:{
id:"1",
name:"ABC Software"
}
},
Person:{
mail:"sASa@sAAsS.it",
OfficePersonTask:[
{
office_id:"1",
person_id:"1",
task_id:"1"
}
]
}
}
]
}What I want is the possibility to show only some field from relative database, so the method that query the database have `$options['fields']` properly setting, so if I want to show person's mail I write:$options['fields'] = array("Person.mail");but what if I want to show company's id or company's name whice is one level deeper?
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