Re: ajax call content in dialog box without remoteFunction

hi cricket,... 

I did manage that, and the code is slightly different from above,... In my case,... and here is the code if anyone needs it: 

<script type="text/javascript">

$(document).ready(function() {

$('#photo_comments_dialog_<?php echo $photo_comment['PhotoComment']['id'] ?> a').each(function() {

var $link = $(this);

var $dialog = $('<div></div>')

.load($link.attr('href'))

.dialog({

autoOpen: false,

width: 500,

modal: true,

title: 'Report Photo Comment',

});

$link.click(function() {

$dialog.dialog('open');

return false;

});

});

});

</script>

and the link: 

<div id="photo_comments_dialog_<?php echo $photo_comment['PhotoComment']['id'] ?>"><?php echo $html->link(__('report', true), '/report/photo_comment/' . $photo_comment['PhotoComment']['id'], array('class' => 'report')) ?></div> 

thank You guys All ! 

Salute, 

chris

On Saturday, March 9, 2013 3:11:24 PM UTC-8, cricket wrote:

You're getting a new window because your link's click event has
window.open() attached to it.

What does this have to do with CakePHP, anyway?

On Sat, Mar 9, 2013 at 4:33 PM, Chris <chri...@yahoo.com> wrote:
> hi there,… can you help me please,…
> I'm trying to load dialog page, but instead I'm getting new window popup,…
> how can I accomplish this,…?
>
> hi guys,... can anyone help,...?
> this is what I got so far,... I'm trying to load jquery dialog page, but
> instead I'm getting new window popup,... how can I accomplish this,...?
>
>  <script>
> $(document).ready(function() {
> $('#photo_comments_opener_<?php echo $photo_comment['PhotoComment']['id']
> ?>').each(function() {
> var $link = $(this);
> var $dialog = $('<div></div>')
> .load($link.attr('href') + ' #content')
> .dialog({
> autoOpen: false,
> title: $link.attr('title'),
> width: 500,
> height: 300
> });
>
> $link.click(function() {
> $dialog.dialog('open');
>
> return false;
> });
> });
>
> });
>   </script>
>
> and here is the link:
>
> <?php echo $html->link(__('report/spam', true), '/report/photo_comment/' .
> $photo_comment['PhotoComment']['id'], array('id' =>
> "photo_comments_opener_".$photo_comment['PhotoComment']['id'], 'class' =>
> 'report',  'onclick' => "window.open(this.href, 'popupwindow', 'width=500,
> height=300'); return false;")) ?>
>
> thanks in advance
> chris
>
>
> On Thursday, March 7, 2013 5:23:46 PM UTC-8, Chris wrote:
>>
>> hi guys,... can anyone help please ,...
>> how can I call content from another page into a dialog box without
>> remoteFunction,... any other way,...?
>>
>> <script type="text/javascript">
>> <?php echo $ajax->remoteFunction(array('url' => array('controller' =>
>> 'photo_comment', 'action' => 'report_spam/',
>> $photo_comment['PhotoComment']['id']), 'update' =>
>> "photo_comments_reports_".$photo_comment['PhotoComment']['id'] )); ?>
>> </script>
>> this is what I currently have,... but it's conflicting with remoteFunction
>> in remoteFunction page.
>>
>> thanks in advance
>> chris
>>
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