Not directly, but with a behavior I did it...
-- In the conditions instead of using
'local'=>'Cascavel - PR'
My behavior check if is a virtualfield and turns the condition query into this:
"CONCAT({$this->alias}.city,' - ',{$this->alias}.state)"=>"Cascavel - PR"
for example,
Em quinta-feira, 5 de dezembro de 2013 00h57min03s UTC-2, Simon Males escreveu:
Em quinta-feira, 5 de dezembro de 2013 00h57min03s UTC-2, Simon Males escreveu:
You cannot search a virtualField... it is virtual.
You'll have to search the columns directly.
On Thu, Dec 5, 2013 at 3:17 AM, André Luis <cava...@live.com> wrote:
> Hi everyone, i have a table "clients" wich the model is "Client"... and in
> my table I have the fields "city" and "state" and others... Also I have the
> following virtualfield:
> public $virtualFields = array(
> 'local'=>"CONCAT(Client.city,' - ',Client.state)",
> );
>
> When i use a find "all" with the conditions 'Client.local'=>'Cascavel - PR'
> it works perfectly... but if I try to find with the conditions
> 'Client.local'=>array('Cascavel - PR','Toledo - PR'), cake gives me an error
> saying that the field Client.local doesnt exists...
>
> Does anyone know where i am wrong??
>
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