Re: 3.0 - routing bug?

The reason i need to parse and generate again an url is in the example I gave in my first message:

In my App, when a user logs in, he is redirected to $this->Auth->redirectUrl() which is of the form /locale/controller/action/param . Before redirecting him, I want to replace "locale" with $user->locale. So I parse the url, replace the locale parameter, and generate the url again.

Does it make sense :) ?

Le jeudi 19 mars 2015 02:09:10 UTC-7, José Lorenzo a écrit :

Router::url() and Router::parse() are not symmetrical. I don't see the reason why you want to parse the url and the pass it again to the Router. Could you explain? 

On Thursday, March 19, 2015 at 1:00:16 AM UTC+1, Pgbi wrote:

Tell me if i'm wrong but i thought that Router::parse was the inverse of Router::url.

In other words, I thought that $url == Router::url(Router::parse($url))would always be true.

Just found out this was not the case.

If $url = "/users/view/123" then Router::url(Router::parse($url)) = "/users/view?pass%5B0%5D=123"

This leads to the following bug in my App:

// In UsersController

function login()

{

    if ($this->request->is('post')) {

        $user = $this->Auth->identify();

        if ($user) {

            $this->Auth->setUser($user);

            $url = $this->Auth->redirectUrl(); // let's say redirect url is "/en/users/view/123"

            $url = Router::parse($url); // now url is ['controller' => 'users', 'action' => 'view', 'locale' => 'en', 'pass' => ['123']]

            $url['locale'] = $user['locale']; // my user is french

            $url = Router::url($url); // now url is "/fr/users/view?pass%5B0%5D=123" instead of "/fr/users/view/123"

            return $this->redirect($url);

        }

    }

}

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