Re: Learning cakePHP debugging

@Martin, thanks. debug($activeUser); returns the type of output I was
expecting.

@abc, I'll look into the php version also.

Now on to my problem, once I actually stopped to _read_ the debug
output I realized that the $activeUser variable is NOT CHANGING when I
log out and log back in again. In addition to the partial setup that I
described above, here are the login and logout functions in my
users_controller.php:

function login() {
if( $this->Auth->user() ) {
// Redirect to start page.
$this->redirect( array('controller' => 'pages', 'action' =>
'start') );
}
} // end login()

function logout() {
$this->Session->destroy();
$this->Session->SetFlash(__('Successfully logged out', true));
$this->redirect( array('controller' => 'pages', 'action' =>
'home') );
} // end logout()

I am using php 5.2.9-1 and cakePHP 1.2.3.8166.

Thanx again, McS.

--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "CakePHP" group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to cake-php+unsubscribe@googlegroups.com
For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
-~----------~----~----~----~------~----~------~--~---