Re: show url parameters in a view

in one view print_r $this->params

pr($this->params);

you can just use:

print $this->params["pass"]["0"];

or you can set variables from controller

http://book.cakephp.org/view/978/Interacting-with-Views

--
Tilen Majerle

http://majerle.eu

2010/10/26 Briko03 <nathanrlarkin@gmail.com>

I am not sure how to display it on the page. I am very new to cakephp.

On Oct 26, 11:37 am, Tilen Majerle <tilen.maje...@gmail.com> wrote:
> so now, what actually you want...u have it in $this->params, so where is
> problem? :D
> --

> Tilen Majerlehttp://majerle.eu
>
> 2010/10/26 Briko03 <nathanrlar...@gmail.com>

>
> > I have an action that is going to display results by the person...
>
> > function person($lname,$fname)
> >    {..........blah blah......}
>
> > I have my person.ctp file that I want so show the url parameters...
> > for example see below
>
> > url: domin.com/controller/action/$lname/$fname
>
> > <h1>Results for $lname</h1>
>
> > I know they are available in $this->params['pass'] however I am not
> > sure how to use them in this instance....
>

> > Check out the new CakePHP Questions sitehttp://cakeqs.organd help others

> > with their CakePHP related questions.
>
> > You received this message because you are subscribed to the Google Groups
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Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions.

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