Thursday, April 28, 2011

Re: Some problem on the hasmany relationship

That's probably because the first value is the array key and you can't have duplicate array keys (your desired result is impossible in PHP). Imagine it as a select list; each option would have the same value (1), which defeats the object. Cake is (in essence) simply doing a loop, adding each value it finds to the resulting array and that will always replace the last value found (it's always array key '1'); hence you end up with the 'last' record. Would it work for you to switch the columns around? That would give you the three values you need.

Jeremy Burns
Class Outfit

jeremyburns@classoutfit.com
http://www.classoutfit.com

On 28 Apr 2011, at 11:13, jackgoh wrote:

> When use find('list',....), it is:
> Array
> (
> [1] => 4
> )
>
>
> But the result suppose is :
>
>
> Array
> (
> [1] => 7
> [1] => 14
> [1] => 4
> )
>
> It is always get the last record.
>
> Thanks
>
> On Apr 28, 3:14 pm, Jeremy Burns | Class Outfit
> <jeremybu...@classoutfit.com> wrote:
>> What are the results of find list?
>>
>> Jeremy Burns
>> Class Outfit
>>
>> jeremybu...@classoutfit.comhttp://www.classoutfit.com
>>
>> On 28 Apr 2011, at 07:19, jackgoh wrote:
>>
>>
>>
>>> Hi Jeremy,
>>
>>> - There is a missing ' before category_id after
>>> 'associationForeignKey'
>>> => sorry, my typo in this content only. sorry.
>>
>>> - Your conditions in the find->list look wrong; try 'conditions' =>
>>> array('stock_id' => $this->Stock->id)
>>> => The results are the same. both ways are working, but your
>>> suggestion way is better. ;)
>>
>>> - The convention is to name your joining table CategoryStock (the two
>>> models are in alphabetical order). Although your arrangement ought to
>>> work, I generally stay with conventions unless there is a compelling
>>> reason not to.
>>> => I changed it as what you suggested. (in Stock model & StockCategory
>>> model)
>>
>>> - Do you have a model for StockCategory?
>>> => Yes:
>>> class CategoryStock extends AppModel
>>> {
>>> var $name = CategoryStocks;
>>> }
>>
>>> - What happens when you use find 'all' rather than 'list'?
>>> => i got the correct array!! But the result look like:
>>> Array
>>> (
>>> [0] => Array
>>> (
>>> [CategoryStock] => Array
>>> (
>>> [stock_id] => 1
>>> [business_category_id] => 4
>>> )
>>
>>> )
>>
>>> [1] => Array
>>> (
>>> [CategoryStock] => Array
>>> (
>>> [stock_id] => 1
>>> [business_category_id] => 7
>>> )
>>
>>> )
>>> [2] => Array
>>> (
>>> [CategoryStock] => Array
>>> (
>>> [stock_id] => 1
>>> [business_category_id] => 14
>>> )
>>
>>> )
>>
>>> )
>>
>>> - What happens when you die(debug($selectedRecord)) in your controller
>>> before passing it to your view?
>>> => same as above result.
>>
>>> Out of interest, what does the resulting SQL look like?
>>> => (i simplified) :SELECT CategoryStock.* FROM `stock_CategoryStocks`
>>> AS `CategoryStock` WHERE `stock_id` = 1 , effected rows is 3 , which
>>> is always correct, when use the find('list'), the effected rows is
>>> still 3, but debug($selectedRecord) show only 1 record in the array.
>>> Weird.
>>
>>> Thanks.
>>
>>> Regards
>>> Jack
>>
>>> On Apr 28, 12:03 pm, Jeremy Burns | Class Outfit
>>> <jeremybu...@classoutfit.com> wrote:
>>>> These might be typos but some of the code looks *slightly* odd.
>>
>>>> - There is a missing ' before category_id after 'associationForeignKey'
>>>> - Your conditions in the find->list look wrong; try 'conditions' => array('stock_id' => $this->Stock->id)
>>>> - The convention is to name your joining table CategoryStock (the two models are in alphabetical order). Although your arrangement ought to work, I generally stay with conventions unless there is a compelling reason not to.
>>>> - Do you have a model for StockCategory?
>>>> - What happens when you use find 'all' rather than 'list'?
>>>> - What happens when you die(debug($selectedRecord)) in your controller before passing it to your view?
>>
>>>> Out of interest, what does the resulting SQL look like?
>>
>>>> Jeremy Burns
>>>> Class Outfit
>>
>>>> jeremybu...@classoutfit.comhttp://www.classoutfit.com
>>
>>>> On 27 Apr 2011, at 22:51, jackgoh wrote:
>>
>>>>> Hi cricket,
>>
>>>>> The $this->Stock->id is set correctly. And the SQL is working
>>>>> perfectly, i can get the correct number of records (which 3 of them:
>>>>> 4, 7, 14)
>>
>>>>> On Apr 27, 1:53 am, cricket <zijn.digi...@gmail.com> wrote:
>>>>>> Is $this->Stock->id set to something? What does the SQL look like? Set
>>>>>> debug to 2 to see it.
>>
>>>>>> On Mon, Apr 25, 2011 at 1:25 PM, jackgoh <kockh...@gmail.com> wrote:
>>>>>>> Hi,
>>
>>>>>>> I am facing some problem when deal with a realtionship tables, the
>>>>>>> record is not display :
>>
>>>>>>> // in Stock model:
>>>>>>> var $hasAndBelongsToMany = array(
>>>>>>> 'Category' => array(
>>>>>>> 'className' => 'Category',
>>>>>>> 'joinTable' => 'category',
>>>>>>> 'foreignKey' => 'stock_id',
>>>>>>> 'associationForeignKey' => category_id',
>>>>>>> 'with' => 'StockCategory',
>>>>>>> ),
>>>>>>> );
>>
>>>>>>> // in Stock controller:
>>>>>>> $selectedRecord = $this->Stock->StockCategory->find('list',
>>>>>>> array( 'fields'=>array('stock_id','category_id'),
>>>>>>> 'conditions'=>array('stock_id='.$this->Stock->id) ) );
>>>>>>> $this->set(compact('selectedRecord'));
>>
>>>>>>> I try to copy the SQL by using debug() to phpmysql, and i get 3 lines
>>>>>>> of records. but when i try to PRINT_R the $selectedRecord, i can only
>>>>>>> get 1 record, example:
>>
>>>>>>> Array
>>>>>>> (
>>>>>>> [1] => 4
>>>>>>> )
>>
>>>>>>> Suppose the result have to be :
>>
>>>>>>> Array
>>>>>>> (
>>>>>>> [1] => 4
>>>>>>> [1] => 7
>>>>>>> [1] => 14
>>>>>>> )
>>
>>>>>>> Values : 4,7,14 are category_id, [1] is stock_id. There is a table
>>>>>>> call "category" to store all the category name.
>>
>>>>>>> Please point out whats wrong to my code or logic??
>>
>>>>>>> Thanks
>>
>>>>>>> Best Regards.
>>
>>>>>>> --
>>>>>>> Our newest site for the community: CakePHP Video Tutorialshttp://tv.cakephp.org
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