Friday, January 20, 2012

Re: Including queried information in default layout

Is the load model call the line with the error?

Can you post more code?

The component idea should be fine.

More details of your bab/menu model would be good.

- S

On 20 Jan 2012 16:13, "Dave D" <its.dave.dawson@gmail.com> wrote:
I'm looking to create a site where I can have a navigation list on one
side of each page where the list of links is taken from a database
table.

I can create the list of links just fine in the layout, but I'm suck
looking at how I might be able to get the list out from the database.
I've been looking around the internet to see how I might be able to
work it in, but I haven't been able to find anything that would work
for sure, so I was thinking I should get some input from this group
before I continue.

The first idea I saw was to include the model in the AppController,
but I can't get that to work in the slightest.  I tried putting this
in my AppController:

$this->loadModel('Sitelist');

Which breaks everything, giving me the error: "Parse error: syntax
error, unexpected T_VARIABLE, expecting T_FUNCTION in /path/to/cake/
app/Controller/AppController.php on line 36 ".

I already created a "Sitelist" model, controller and view with basic
CRUD and I'm able to edit everything fine through another page.

I've also seen the suggestion to create a component that gets included
in all of the controllers which queries the database to get the list,
which then gets used by the layout, but I haven't found anything about
that written after version 1.2.

I'm working with CakePHP 2.0.5.  If anybody knows what the proper way
to get a list like this populated, please let me know.

Thanks!

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