Re: bootstrap twitter typeahead , dont work for me in cakephp

Never create a new response object

there is already one available in your controller

just use 

    $this->response->body($content);

as documented

Am Freitag, 16. August 2013 19:16:32 UTC+2 schrieb cesar calvo:

I use this in my AppController

public function jsonResponse($array) {
        return new CakeResponse(array('body' => json_encode($array)));
    }

Then on a controller call jsonResponse


Note: if you are usin Security component on beforeFilter:

if ($this->request->is('ajax')) $this->Security->unlockedActions = array($this->request->action);

On Thursday, August 15, 2013 11:03:34 PM UTC-3, Renato Bigliazzi wrote:

Hi , I can not do the twitter bootstrap component typeahead work with cake. i use https://github.com/rudylee/cbunny , but dont work form me.

In my view

JS

<script type="text/javascript">

 $(document).ready(function(){

$('#itemdesc').typeahead({

    source: function (query, process) {

      return $.ajax({

        url:'<?php echo Router::url(array('controller'=>'Invoices','action'=>'localizaprodutos'));?>',

        type: 'get',

        data: {q: query},

        dataType: 'json',

        success: function (json) {

          return process(json);

        }

      });

    }

  });

});

</script>

HTML

<input type="text" name="itemdesc[]"  class="input-large" id="itemdesc" data-provide="typeahead"/>

and controller

public function localizaprodutos(){

$this->autoRender = false;

        $this->RequestHandler->respondAs('json');

        // get the search term from URL

        $term = $this->request->query['q'];

        $users = $this->Invoice->Invoicedetail->Inventoryitem->find('all',array(

            'conditions' => array(

                'Inventoryitem.desc LIKE' => '%'.$term.'%'

            )

        ));

        // Format the result for select2

        $result = array();

        foreach($produtos as $key => $produto) {

            array_push($result, $produto['Inventoryitem']['desc']);

        }

        $produtos = $result;

        

        echo json_encode($produtos);

    }

Thanks

Renato

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