With the hasOne relationship, the query looks like:
[code]
SELECT `Author`.`id`, `Author`.`name`, COUNT(`Article`.`id`) as
article_count FROM `authors` AS `Author` LEFT JOIN `articles` AS
`Article` ON (`Article`.`author_id` = `Author`.`id`) WHERE
`Author`.`id` IN (1, 2, 13) GROUP BY `Author`.`id`, `Author`.`name`
[/code]
With the hasMany relationship, the query looks like:
[code]
SELECT `Author`.`id`, `Author`.`name`, COUNT(`Article`.`id`) as
article_count FROM `authors` AS `Author` WHERE `Author`.`id` IN (1, 2,
13) GROUP BY `Author`.`id`, `Author`.`name`
[/code]
Contain does not assist in creating a LEFT JOIN, which is why
Article.id is an unknown column!
As far as I remember, the issue is probably not in the Containable
behaviour, but somewhere in DboSource, but I may be wrong here :)
There is another way:
1) Set contain equal false.
2) Define the joins yourself, as in the example below:
[code]
$results = $this->Article->Author->find(
'all',
array(
'contain' => false,
'joins' => array(
array(
'table' => 'articles',
'type' => 'left',
'alias' => 'Article',
'foreignKey' => false,
'conditions' => array('Article.author_id =
Author.id')
)
),
'fields' => array('Author.id', 'Author.name', 'COUNT
(Article.id) as article_count'),
'group' => array('Author.id', 'Author.name'),
)
);
[/code]
But that is also not very simple!
Will keep you updated, should I find a better solution! Enjoy,
John
On Dec 30, 12:07 pm, Jeremy Burns <jeremybu...@me.com> wrote:
> Thank you John - I will try this out. Strikes me as very odd that this
> is not much much simpler!
>
> On Dec 30, 10:05 am, John Andersen <j.andersen...@gmail.com> wrote:
>
> > Hi Jeremy,
>
> > Seems like Contain can't find out to make a join when there is a
> > hasMany relationship between the Author and the Article models. I made
> > changes to Example A, so that Contain makes a LEFT JOIN, which
> > includes Authors with no Articles :)
>
> > 1) Unbind the hasMany relationship.
> > 2) Bind a hasOne relationship.
> > 3) Make the find on the Author model - I have include two author ids
> > with articles and one (13) without articles.
> > [code]
> > $this->Article->Author->unbindModel( array('hasMany' => array
> > ('Article')));
> > $this->Article->Author->bindModel( array('hasOne' => array
> > ('Article')));
> > $results = $this->Article->Author->find(
> > 'all',
> > array(
> > 'contain' => array('Article'),
> > 'fields' => array('Author.id', 'Author.name', 'COUNT
> > (Article.id) as article_count'),
> > 'conditions' => array('Author.id' => array(1,2,13)),
> > 'group' => array('Author.id', 'Author.name'),
> > )
> > );
> > debug($results);
> > [/code]
>
> > The result is:
> > [result]
> > 28871\controllers\articles_controller.php (line 48)
> > Array
> > (
> > [0] => Array
> > (
> > [Author] => Array
> > (
> > [id] => 1
> > [name] => Hans Christian Andersen
> > )
> > [0] => Array
> > (
> > [article_count] => 19
> > )
> > )
> > [1] => Array
> > (
> > [Author] => Array
> > (
> > [id] => 2
> > [name] => Terry Prattchet
> > )
> > [0] => Array
> > (
> > [article_count] => 19
> > )
> > )
> > [2] => Array
> > (
> > [Author] => Array
> > (
> > [id] => 13
> > [name] => Test
> > )
> > [0] => Array
> > (
> > [article_count] => 0
> > )
> > )
> > )
> > [/result]
>
> > Hope this helps you on the way,
> > John
>
> > On Dec 30, 6:52 am, Jeremy Burns <jeremybu...@me.com> wrote:
>
> > > Thanks John. Option B does indeed work - sort of! It returns a list of
> > > location types with a count of their locations, but only where there
> > > is a location. In other words, it does not give me the location types
> > > that do not have have any locations.
>
> > > Any more ideas - anyone?
>
> > > On Dec 29, 12:35 pm, John Andersen <j.andersen...@gmail.com> wrote:
>
> > > > A correction, example A gives the author with all the articles, but
> > > > the article count is 1 (one) - so no luck using that!
> > > > Enjoy,
> > > > John
> > > > [snip]
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