It looks like `Controller::render()` sets the body on the CakeResponse object and then returns the CakeResponse object: http://api.cakephp.org/2.6/source-class-Controller.html#922-962. I would imagine you could access the rendered view like so:
On Wednesday, February 4, 2015 at 5:33:35 PM UTC-5, BrendonKoz wrote:
-- public function test()
{
$this->render('/Emails/html/test' , false);
$emailBody = $this->response->body;
// Do what you want with $emailBody here
}
On Wednesday, February 4, 2015 at 5:33:35 PM UTC-5, BrendonKoz wrote:
For various reasons I had decided to use a 3rd party email library within my current CakePHP project. I thought that it might be nice to use CakePHP's Views to create templating for my emails and take advantage of layouts too. Unfortunately I'm stumped on just how to retrieve the rendered output of a view back to the Controller method.
I've tried the following:
$this->layout = false;
#$this->view = '/Emails/html/test.ctp';
$var = $this->render('/Emails/html/test' , false);
pr($var->_body); die();
}
$var->_body is protected (as denoted by the underscore). I saw no other property within the $var variable that contained the "body" code within my (template) view.
Are there any ways to do this that I'm just not seeing? If so, can I safely presume that layouts would be handled in a similar fashion?
Thank you for any possible help...
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