In these instances I normally include both links in the original view
& then use CSS to hide 1, & JS to toggle them when required. you can
change the class on a parent element using JS to make the toggle
happen...
HTML...
<span id="link_container" class="show_link_1">
<a id="link_1">Link 1</a>
<a id="link_2">Link 2</a>
</spam>
CSS...
#link_container.show_link_1 #link_2 {
display: none;
}
#link_container.show_link_2 #link_1 {
display: none;
}
And then use the JS (in jquery format)...
if ( $( '#link_container' ).hasClass( 'show_link_1' ) ) {
$
( '#link_container' ).removeClass( 'show_link_1' ).addClass( 'show_link_2' );
} else {
$
( '#link_container' ).removeClass( 'show_link_2' ).addClass( 'show_link_1' );
}
There are, of course a couple of other options, including hiding 1 of
the links & using
$( '#link_container a' ).toggle();
... but I prefer the 1st option in case a browser hiccup causes both
links to show at once, meaning they both appear & re-apear at the same
time. Not sure how common a problem this would be though.
T
On Sep 29, 10:49 am, heohni <heidi.anselstet...@consultingteam.de>
wrote:
> Hi,
>
> I have this part of code in my view
>
> <div class="add_details" id="dynbookmark">
> <?php if($this->Bookmark->checkBookmarkStatus($objects[0]
> ['Gesamtobjekt']['OBJ_ID']) == 'bookmark'){
> $image = 'bookmark.png';
> $text = __('Immobilie merken', true);
> $action = 'add';
> }else{
> $image = 'bookmarked.png';
> $text = __('Immobilie vorgemerkt', true);
> $action = 'delete';
> }
> ?>
> <?=$ajax->link($this->Html->image($image).$text,
> array('controller'=>'bookmark', 'action'=>$action, $objects[0]
> ['Gesamtobjekt']['OBJ_ID']), array('escape' => false, 'update' =>
> 'dynbookmark'));?>
> </div>
>
> This shows me on page load if this item is saved on "bookmark" list,
> or not.
> With the Ajax Link I can toogle this t save or to delete this item
> from the bookmarks list.
>
> But to display the correct link I need 3 important infos:
> - the right picture
> - link text ("add me" + "delete me")
> - the controller action name (add / delete)
>
> As far as I understand the ajax link stuff, I can return only a simple
> string?
> How could I create the entire link with all my needed information?
>
> Any ideas or help?
>
> Thanks!!
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