Re: [Cake 2.1.1] AJAX POST with jQuery cross Controller - Bad Request

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On Fri, May 4, 2012 at 5:48 PM, luca capra <luca.capra@gmail.com> wrote:

Hi,
probably you have to configure the SecurityComponent (and eventually use the FormHelper) to permit those types of request to happen.

See:
- http://en.wikipedia.org/wiki/Cross-site_request_forgery
- http://book.cakephp.org/2.0/en/core-libraries/components/security-component.html#restricting-cross-controller-communication
- http://book.cakephp.org/2.0/en/core-libraries/components/security-component.html#csrf-protection



Il 04/05/2012 13:58, jmail ha scritto:

Hi!

I've got application which I am translating from other technology to CakePHP. Application is in about 60% written with AJAX.There are a lot of cross controller sends :/ So I've got a problem because when I am trying to make something similar with Cake I get error 400 - bad request. Of course I am using Security component and I would like to use this component. App it's quite secure with that component. Of course when I am using GET request everything is OK, but when try to use POST request there is a problem. 

I've got Controller MainController with function start

class MainController extends AppController{

function start(){

$this->set('contests', $this->Contest->find('all', array('conditions' => array('Contest.start <= now()', 'Contest.finish > now()', 'Contest.active' => 1, 'Board.status' => 1))));

if(CakeSession::read('user') === null){

$this->layout = 'nonloginlayout';

}

else{

                        $this->render('startlogged');

}

}

}

Then in startlogged.ctp I've got script:

        function moreChances(){

$.prompt.close();

$.prompt(states, {zIndex: 11000});

$.ajax({

url: "/user/invite/"

,async: true

,dataType: "html"

,type: "GET"

,success: function(data){

$.prompt.close();

$.prompt(data, {buttons:{}, zIndex: 11000})

}

});

}

function sendInvite(){

mail = document.getElementById('inviteMail').value;

message = document.getElementById('inviteMessage').value;

$.prompt.close();

$.prompt(states, {zIndex: 11000});

$.ajax({

url: "/user/send_invite?tmp="+Math.random()

,async: false

,data: {test:'doopa'}

,type: "POST"

,dataType: "html"

,success: function(data){

$('#deb').html(data);

}

,error: function(jqXHR, textStatus, errorThrown){

$('#deb').html(errorThrown);

}

});

       }

user/invite just loading a form into a prompt window

        <label>Email address:<br></label>

<input type="text" name="mail" id="inviteMail">

<br>

<label>Message:<br></label>

<textarea name="message" id="inviteMessage"></textarea>

<br><br>

<div class="floatRight">

<a href="javascript:sendInvite()" style="color: #636363;"><b>send</b></a>

</div>

and User controller look like this

class UserController extends AppController{

function beforeFilter() {

parent::beforeFilter();

$json_actions = array('send_invite');

if(in_array($this->action, $json_actions)){

$this->Security->validatePost = false = array('Session', 'RequestHandler', 'ImageConverter');

}

}

function invite(){

$this->layout = '';

}

function send_invite(){

$this->autoRender = false;

var_dump($_POST);

}

}

And I don't know what to do more. Every POST request generating error:

2012-05-04 13:54:27 Error: [BadRequestException] The request has been black-holed

#0 !!!Path_to_root!!!\lib\Cake\Controller\Component\SecurityComponent.php(227): SecurityComponent->blackHole(Object(UserController), 'csrf')

Can some please help me? I don't know what to do to not get black-holed. I am desperate because of that three of my projects are stoped :(

Thanks for all.

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