Re: How lo load a model from a model?

Use:

$this->load('Objeckt); instead of App::uses()

Em terça-feira, 6 de março de 2012 08h14min42s UTC-3, heohni escreveu:

Hi,

class DetailsController extends AppController{
var $name = 'Detail';

public function index($id){
if($id){
    $results = $this->Detail->find('first', $conditions['Gesamtobjekt']);

    App::uses('Objekt', 'Model');
    $results = $this->Objekt->translateStrings($results);debug($results);
}
}
}

What do I have to do, to get the  $this->Objekt->translateStrings working?
Right niow, I only get

Fatal error: Call to a member function translateStrings() 

Message.

What do I miss?

I tried to get an info from the book, but I only find how to write the App::uses but I didn't find any further note..

Please advice! 

--
Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions.
 
 
To unsubscribe from this group, send email to
cake-php+unsubscribe@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php