function manage_edit($id = null)
{
if ($this->RequestHandler->isAjax()) {
Configure::write('debug', 0);
$award = $this->Award->getAward($id, $this->Auth->user('id'));
if (!empty($award)) {
$this->layout = 'ajax';
if (!empty($this->data)) {
$this->autoLayout = false;
$this->autoRender = false;
$this->Award->id = $id;
$black = array('id', 'profile_id', 'created');
if ($this->Award->save($this->data, true,
array_diff(array_keys($this->Award->schema()), $black))) {
$this->set('award', $this->Award->getAward($id,
$this->Auth->user('id')));
$response['status'] = true;
$response['html'] =
$this->render('/elements/awards/view_block', 'ajax');
$this->header('Content-Type: application/json');
echo json_encode($response);
exit();
} else {
$this->set('errors',
$this->Award->validationErrors);
$this->data = $award;
$response['status'] = false;
$response['html'] =
$this->render('/elements/awards/manage_edit', 'ajax');
$this->header('Content-Type: application/json');
echo json_encode($response);
exit();
}
}
if (empty($this->data)) {
$this->data = $award;
$this->render('/elements/awards/manage_edit', 'ajax');
}
}
} else {
$this->redirect(array('manage' => true, 'action' =>
'index'));
}
$this->set('errors', $this->Award->validationErrors);
}
So this returns noting to the page. I am updating a div and spitting out the
$response['html'] to the specific div which returns only the element. One
thing is the exit(); I think that's what I forgot to mention seems to not
echo out the actual view / element.
Give that a try.
Dave
-----Original Message-----
From: cake-php@googlegroups.com [mailto:cake-php@googlegroups.com] On Behalf
Of thomaus
Sent: January-29-10 6:50 AM
To: CakePHP
Subject: Re: JSON View
Hi Dave,
I tried it this way but it's the same.
$this->layout = 'ajax';
$this->autoLayout = false;
$this->autoRender = false;
$response['html'] = $this->render('/form/form_json');
So is there a way to get the result content of a view in a var (in this case
$response['html']) without rendering it (= without getting the annoying
echo) ?
thomas...
On Jan 28, 4:57 pm, "Dave" <make.cake.b...@gmail.com> wrote:
> Hey,
> Simply include
>
> $this->layout = 'ajax';
> $this->autoLayout = false;
> $this->autoRender = false;
>
> In the controller action to stop the view from output. All you get is
> the json data then do what you need with it
>
> Dave
>
> -----Original Message-----
> From: cake-php@googlegroups.com [mailto:cake-php@googlegroups.com] On
> Behalf Of thomaus
> Sent: January-28-10 9:08 AM
> To: CakePHP
> Subject: Re: JSON View
>
> Hi there,
>
> I need to render a full HTML view with header, css and js includes and
> pass it as a JSON.
>
> I liked Dave's trick :
>
> $response['html'] = $this->render('my_view_needed'); Then echo back my
> json_encode($response) and use response.html in the js to render the
> view / messages / errors.
>
> But there is a problem, when you do : $response['html'] =
> $this->render ('my_view_needed'); it correctly puts all the HTML view
> content in your $response['html'] var but still it outputs the view
> content just after so the JSON callback format is incorrect. Is there
> a way to get the content of a view render without rendering it?
>
> Otherwise how can I do if I want to send the full HTML content of my
> view as a JSON callback?
>
> Thanks in advance.
>
> On Jan 21, 8:03 am, Akeda Bagus <ad...@gedex.web.id> wrote:
> > On Mon, Jan 11, 2010 at 10:50 PM, Dave <make.cake.b...@gmail.com> wrote:
> > > Does anyone know how to return a JSON object from an ajax request
> > > to return the view and a success status? I see all these tutorials
> > > to retrn data but no html. Everything is layout = false,
> > > autoRender = false. I can return the view in normal html but I
> > > need to get a status = true or false to the js to tell it what to
> > > do next depending on the status. I need to update 1 of 2 possible
> > > divs with the response and that's why I need the success to tell
> > > the js if success
> update this div if no success then do something different.
>
> > > I need to return a view along with my success or fail status. Not
> > > just an error message as I have found in my json / cakephp searching.
>
> > > so in the controller
> > > $this->layout = 'ajax';
> > > if(this->Model->save())
> > > {
> > > //return success = true and success view $respounse = array('status'
> > > => true, 'html' => ???
>
> > > } else {
>
> > > //return false
> > > $respounse = array('status' => false); }
> > > $this->header('Content-Type: application/json');
> > > echo json_encode($response);
>
> > > Ideas?
>
> > My approach is:
> > 1. create json layout in views/layout/json/default.ctp which contains:
> > <?php
> > header("Pragma: no-cache");
> > header("Cache-Control: no-store, no-cache, max-age=0,
> > must-revalidate");
> > header('Content-Type: application/json');
>
> > echo $content_for_layout;
> > ?>
>
> > 2. create common view for json, says app/views/common/jsonize.ctp --
> > my controllers use this oftenly, which contains:
> > <?php echo $javascript->object($result); ?>
>
> > 3. I put jsonize in app_controller.php, so other controllers will
> > benefit
> this:
> > function jsonize() {
> > $this->layout = 'json/default';
> > $this->viewPath = "common";
>
> > if ( Configure::read('debug') > 0 ) {
> > Configure::write('debug', 0);
> > }
>
> > if ( !$this->params['named'] ) {
> > $this->Session->setFlash('Invalid parameter for JSON',
> > 'error');
> > $this->redirect(array('action'=>'index'));
> > }
>
> > foreach ($this->params['named'] as $field => $value) {
> > $like = str_replace('*', '%', $value);
> > $condition[Inflector::singularize($this->name).".$field
> > LIKE"] = $like;
> > }
> > $this->{Inflector::singularize($this->name)}->recursive = -1;
> > $result =
> > $this->{Inflector::singularize($this->name)}->find('all',
> > array( 'conditions' => $condition ));
> > $this->set('result', $result);
>
> > }
>
> > It just a little modification is you used on $this->Model->save()
>
> > --
> > regards,
> > gedex
>
> > blog:http://gedex.web.id
>
> Check out the new CakePHP Questions sitehttp://cakeqs.organd help
> others with their CakePHP related questions.
>
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