CakePHP 2 + JQuery Easy UI

Hi people, I´m from Venezuela sorry my english.

I have a little problem and I need your help

I need to work with Jquery Easy UI (http://www.jeasyui.com) and with
Cakephp together.

But I can´t do it work.

I make the query in the controller and return the data in Json format:

function getPaises(){
$this->autoRender= false;
Configure::write('debug', 0);

$paises = $this->Pais->find(
'all',
array(
'fields'=>array(
'Pais.id',
'Pais.nombre'
)
)
);

return (json_encode($paises));
}

In view, I have:

<table id="tt"></table>


<input type="hidden" id="url-listado-paises" value="<?php echo $this-
>Html->url(array('controller'=>'paises','action'=>'getPaises')); ?>"/>

<script>
$('#tt').datagrid({
url:$('#url-listado-paises').val(),
columns:[[
{
'Pais': {
field:'id',title:'ID',width:100,
field:'nombre','title':'Nombre'
}
}
]]
});
</script>

But it doesn´t work

Any idea why?

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