Sunday, August 30, 2009

Re: Using belongsTo and hasMany relationships: Is it possible to access tables through a chain of relationships?

ok... but I'm still not sure exactly what your intent is. When you say
you need information on THE user's animal - do you mean there is a
particular user that you are trying to get information on, like the
current requesting user? $id is a unique value in your method (ie. not
a loop iterator or something)? If so, why have find('all') and
'order'=>array('User.id'=>'asc')? Part of my confusion is that you
don't have a well-defined belongsTo relationship between Userpages and
Users - which user does a page with approved = 1 belongTo? But if you
need only info on the user with 'id'=>$id, set 'conditions' at the
User model level as well:

$array = $this->User->find('first', array(
'conditions'=>array('id'=>$id),
'fields'=>array('id', 'animal_id'),
'contain'=>array(
'Animal'=>array(
'fields'=>array
('frontfilename')
),
'Userpage'=>array(
'conditions'=>array(
'or'=>array(

'approved'=>1,
'and'=>array(
'Userpage.approved' => -1,
'user_id' => $id
)
)
),
'order'=>array(
'id'=>'desc')
)
)
)
);

I think this thread might be straying outside the scope of cakephp
into program design details :)

On Aug 31, 7:14 am, Sarah <sarah.e.p.jo...@gmail.com> wrote:
> I'm performing this in the Userpages controller.  I was calling find
> on Users because I need information on the user's animal.
>
> User hasMany Userpages
> User belongsTo Animal
> The foreign keys are set up appropriately.
>
> I need to get a list of all userpages in which: (Userpages.approved =
> 1) OR (Userpages.approved = -1 AND User.id/user_id = $id)
>
> But I want the following information: the Userpage id, the userpage
> user_id, and the frontfilename from the user's animal.
>
> The concept is similar to a list of comments:
> I want the id and contents of the comment, I want the information on
> the user, including the user's picture (in this case frontfilename
> which is a column in Animal).
>
> I suppose the catch is that more than one user can be the same animal
> (users are in groups).
>
> I've been searching everything that I can think of and searching based
> off what I find.  Do you think the kind of join matters?
>
> I appreciate your following up and your help.
>
> Thank you,
> ~Sarah
>
> On Aug 30, 1:28 am, delocalizer <conrad.leon...@hotmail.com> wrote:
>
>
>
> > Ah I hadn't realised you just wanted Userpages - in which case why not
> > call find on Userpage?
> > If you're in Users controller:
> > $pages = $this->User->Userpage->find('all',array(
> >     'conditions'=>array(
> >          'or'=>array(
> >              'approved'=>1,
> >              'and'=>array(
> >                  'Userpage.approved' => -1,
> >                  'user_id' => $id
> >              )
> >          )
> >      )
> > ))
>
> > On Aug 30, 3:21 pm, Sarah <sarah.e.p.jo...@gmail.com> wrote:
>
> > > Wow, this was very cool.  Thank you for the advice.
>
> > > I realized I had forgotten a condition.  So this is where I am now:
>
> > >                  $array = $this->User->find('all', array(
> > >                         'fields'=>array('id', 'animal_id'),
> > >                         'order'=>array('User.id'=>'asc'),
> > >                         'contain'=>array(
> > >                                 'Animal'=>array(
> > >                                         'fields'=>array
> > > ('frontfilename')
> > >                                 ),
> > >                                 'Userpage'=>array(
> > >                                         'conditions'=>array(
> > >                                                 'or'=>array(
> > >                                                         'approved'=>1,
> > >                                                         'and'=>array(
>
> > > 'Userpage.approved' => -1,
>
> > > 'user_id' => $id
> > >                                                         )
> > >                                                 )
> > >                                         ),
> > >                                         'order'=>array(
> > >                                                 'id'=>'desc')
> > >                                         )
> > >                                 )
> > >                         )
> > >                 );
>
> > > This does not cause any errors.  :)  However, I'm not quite sure that
> > > this is what I need.  To my understand based of the reading on
> > > containable (and the results that I received from the query), this
> > > query will return all users and only return their userpage information
> > > if it matches the conditions.  I suppose I could just check each user
> > > from the query to see if that user had any userpage info returned by
> > > the query, but I imagine this would slow things down?
>
> > > I thank you very much for your time and help.  I would appreciate any
> > > advice you can give.  :)
>
> > > Thanks,
> > > ~Sarah
>
> > > On Aug 29, 1:08 am, delocalizer <conrad.leon...@hotmail.com> wrote:
>
> > > > Hi Sarah,
> > > > If you have a reasonably complicated find query with associated models
> > > > and conditions, the core 'Containable' behaviour is very handy:http://book.cakephp.org/view/474/Containable
> > > > so in your AppModel put this (and all your models will have access to
> > > > the behaviour):
> > > > var $actsAs = array('Containable');
> > > > then you would have for your query something like this:
> > > > $array = $this->User->find('all',array(
> > > >     'fields'=>array('id','animal_id'),
> > > >     'order'=>array('id'=>'asc'),
> > > >     'contain'=>array(
> > > >          Animal=>array(
> > > >             fields=>array('frontfilename')
> > > >          ),
> > > >          Userpage=>array(
> > > >             'conditions'=>array(
> > > >                 'approved' => '1'
> > > >             ),
> > > >             'order'=>array(
> > > >                 'id'=>'desc')
> > > >          )
> > > >     )
> > > > ));
> > > > Note that conditions, fields and order options are all specified on a
> > > > per-model basis  - you get back only what you want from each model.
> > > > Containable is definitely worth the effort to learn.
>
> > > > cheers,
> > > > C.
>
> > > > On Aug 29, 7:40 am, Sarah <sarah.e.p.jo...@gmail.com> wrote:
>
> > > > > I fixed my syntax,
>
> > > > > $conditions = array('or' => array( 'Userpage.approved' => 1, 'User.id'
> > > > > => $id) );
> > > > > $order = array('User.id ASC', 'Userpage.id DESC');
> > > > > $array = $this->User->find('all', array('fields'=>array('id',
> > > > > 'Userpage.id', 'User.animal_id', 'Animal.frontfilename'),
> > > > > 'conditions'=>$conditions, 'order'=>$order));
>
> > > > >  but I'm still getting the same errors as before.
>
> > > > > I verified that a User has many userpage and that a userpage belongs
> > > > > to a user.
> > > > > The SELECTing of the Animal picture is not a problem...I don't
> > > > > understand why it won't SELECT the userpage information...
>
> > > > > My recursive level is set to 1, I tried setting it to 2, but it didn't
> > > > > make a difference.
>
> > > > > Thanks for your time and help,
> > > > > ~Sarah
>
> > > > > On Aug 28, 12:23 pm, WebbedIT <p...@webbedit.co.uk> wrote:
>
> > > > > > Looks like you very nearly had it.  Just got your find syntax slightly
> > > > > > wrong, try:
>
> > > > > > $array = $this->User->find('all', array(
> > > > > >   'fields'=>array('id, 'Userpage.id', 'User.animal_id',
> > > > > > 'Animal.frontfilename'),
> > > > > >   'conditions'=>$conditions,
> > > > > >   'order'=>$order
> > > > > > );
>
> > > > > > Then go have a look at the cookbook and study the syntax of the find
> > > > > > command a bit more.  The first parameter should be the type of call,
> > > > > > in this instance 'all'.
>
> > > > > > The second parameter needs to be an array with your fields,
> > > > > > conditions, order etc.
>
> > > > > > Hope this helps
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